#
Step-by-Step Solution
for Friday 23rd September Diabolical

## Before

## Step

## After

For box 1, candidates for 3 are all in row 2, so you can remove candidates from other blocks.

Either candidate for cell (4,8) forces 2 into cell (4,2).

For box 2, candidates for 5 are all in row 3, so you can remove candidates from other blocks.

For box 7, candidates for 5 are all in row 7, so you can remove candidates from other blocks.

Either candidate for cell (9,2) forces 5 into cell (1,7).

Either candidate for cell (1,1) forces 3 into cell (3,4).

Either candidate for cell (9,2) forces 3 into cell (9,3).

Either candidate for cell (9,2) forces 6 into cell (8,3).

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